(** * ProofObjects: The Curry-Howard Correspondence *)
Set Warnings "-notation-overridden,-parsing".
From LF Require Export IndProp.
(** "_Algorithms are the computational content of proofs_." --Robert Harper *)
(** We have seen that Coq has mechanisms both for _programming_,
using inductive data types like [nat] or [list] and functions over
these types, and for _proving_ properties of these programs, using
inductive propositions (like [even]), implication, universal
quantification, and the like. So far, we have mostly treated
these mechanisms as if they were quite separate, and for many
purposes this is a good way to think. But we have also seen hints
that Coq's programming and proving facilities are closely related.
For example, the keyword [Inductive] is used to declare both data
types and propositions, and [->] is used both to describe the type
of functions on data and logical implication. This is not just a
syntactic accident! In fact, programs and proofs in Coq are
almost the same thing. In this chapter we will study how this
works.
We have already seen the fundamental idea: provability in Coq is
represented by concrete _evidence_. When we construct the proof
of a basic proposition, we are actually building a tree of
evidence, which can be thought of as a data structure.
If the proposition is an implication like [A -> B], then its proof
will be an evidence _transformer_: a recipe for converting
evidence for A into evidence for B. So at a fundamental level,
proofs are simply programs that manipulate evidence. *)
(** Question: If evidence is data, what are propositions themselves?
Answer: They are types! *)
(** Look again at the formal definition of the [even] property. *)
Print even.
(* ==>
Inductive even : nat -> Prop :=
| ev_0 : even 0
| ev_SS : forall n, even n -> even (S (S n)).
*)
(** Suppose we introduce an alternative pronunciation of "[:]".
Instead of "has type," we can say "is a proof of." For example,
the second line in the definition of [even] declares that [ev_0 : even
0]. Instead of "[ev_0] has type [even 0]," we can say that "[ev_0]
is a proof of [even 0]." *)
(** This pun between types and propositions -- between [:] as "has type"
and [:] as "is a proof of" or "is evidence for" -- is called the
_Curry-Howard correspondence_. It proposes a deep connection
between the world of logic and the world of computation:
propositions ~ types
proofs ~ data values
See [Wadler 2015] (in Bib.v) for a brief history and up-to-date exposition. *)
(** Many useful insights follow from this connection. To begin with,
it gives us a natural interpretation of the type of the [ev_SS]
constructor: *)
Check ev_SS.
(* ===> ev_SS : forall n,
even n ->
even (S (S n)) *)
(** This can be read "[ev_SS] is a constructor that takes two
arguments -- a number [n] and evidence for the proposition [even
n] -- and yields evidence for the proposition [even (S (S n))]." *)
(** Now let's look again at a previous proof involving [even]. *)
Theorem ev_4 : even 4.
Proof.
apply ev_SS. apply ev_SS. apply ev_0. Qed.
(** As with ordinary data values and functions, we can use the [Print]
command to see the _proof object_ that results from this proof
script. *)
Print ev_4.
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0)
: even 4 *)
(** Indeed, we can also write down this proof object _directly_,
without the need for a separate proof script: *)
Check (ev_SS 2 (ev_SS 0 ev_0)).
(* ===> even 4 *)
(** The expression [ev_SS 2 (ev_SS 0 ev_0)] can be thought of as
instantiating the parameterized constructor [ev_SS] with the
specific arguments [2] and [0] plus the corresponding proof
objects for its premises [even 2] and [even 0]. Alternatively, we can
think of [ev_SS] as a primitive "evidence constructor" that, when
applied to a particular number, wants to be further applied to
evidence that that number is even; its type,
forall n, even n -> even (S (S n)),
expresses this functionality, in the same way that the polymorphic
type [forall X, list X] expresses the fact that the constructor
[nil] can be thought of as a function from types to empty lists
with elements of that type. *)
(** We saw in the [Logic] chapter that we can use function
application syntax to instantiate universally quantified variables
in lemmas, as well as to supply evidence for assumptions that
these lemmas impose. For instance: *)
Theorem ev_4': even 4.
Proof.
apply (ev_SS 2 (ev_SS 0 ev_0)).
Qed.
(* ################################################################# *)
(** * Proof Scripts *)
(** The _proof objects_ we've been discussing lie at the core of how
Coq operates. When Coq is following a proof script, what is
happening internally is that it is gradually constructing a proof
object -- a term whose type is the proposition being proved. The
tactics between [Proof] and [Qed] tell it how to build up a term
of the required type. To see this process in action, let's use
the [Show Proof] command to display the current state of the proof
tree at various points in the following tactic proof. *)
Theorem ev_4'' : even 4.
Proof.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_SS.
Show Proof.
apply ev_0.
Show Proof.
Qed.
(** At any given moment, Coq has constructed a term with a
"hole" (indicated by [?Goal] here, and so on), and it knows what
type of evidence is needed to fill this hole.
Each hole corresponds to a subgoal, and the proof is
finished when there are no more subgoals. At this point, the
evidence we've built is stored in the global context under the name
given in the [Theorem] command. *)
(** Tactic proofs are useful and convenient, but they are not
essential: in principle, we can always construct the required
evidence by hand, as shown above. Then we can use [Definition]
(rather than [Theorem]) to give a global name directly to this
evidence. *)
Definition ev_4''' : even 4 :=
ev_SS 2 (ev_SS 0 ev_0).
(** All these different ways of building the proof lead to exactly the
same evidence being saved in the global environment. *)
Print ev_4.
(* ===> ev_4 = ev_SS 2 (ev_SS 0 ev_0) : even 4 *)
Print ev_4'.
(* ===> ev_4' = ev_SS 2 (ev_SS 0 ev_0) : even 4 *)
Print ev_4''.
(* ===> ev_4'' = ev_SS 2 (ev_SS 0 ev_0) : even 4 *)
Print ev_4'''.
(* ===> ev_4''' = ev_SS 2 (ev_SS 0 ev_0) : even 4 *)
(** **** Exercise: 2 stars, standard (eight_is_even)
Give a tactic proof and a proof object showing that [even 8]. *)
Theorem ev_8 : even 8.
Proof.
(* FILL IN HERE *) Admitted.
Definition ev_8' : even 8
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
(** [] *)
(* ################################################################# *)
(** * Quantifiers, Implications, Functions *)
(** In Coq's computational universe (where data structures and
programs live), there are two sorts of values with arrows in their
types: _constructors_ introduced by [Inductive]ly defined data
types, and _functions_.
Similarly, in Coq's logical universe (where we carry out proofs),
there are two ways of giving evidence for an implication:
constructors introduced by [Inductive]ly defined propositions,
and... functions! *)
(** For example, consider this statement: *)
Theorem ev_plus4 : forall n, even n -> even (4 + n).
Proof.
intros n H. simpl.
apply ev_SS.
apply ev_SS.
apply H.
Qed.
(** What is the proof object corresponding to [ev_plus4]?
We're looking for an expression whose _type_ is [forall n, even n ->
even (4 + n)] -- that is, a _function_ that takes two arguments (one
number and a piece of evidence) and returns a piece of evidence!
Here it is: *)
Definition ev_plus4' : forall n, even n -> even (4 + n) :=
fun (n : nat) => fun (H : even n) =>
ev_SS (S (S n)) (ev_SS n H).
(** Recall that [fun n => blah] means "the function that, given [n],
yields [blah]," and that Coq treats [4 + n] and [S (S (S (S n)))]
as synonyms. Another equivalent way to write this definition is: *)
Definition ev_plus4'' (n : nat) (H : even n)
: even (4 + n) :=
ev_SS (S (S n)) (ev_SS n H).
Check ev_plus4''.
(* ===>
: forall n : nat, even n -> even (4 + n) *)
(** When we view the proposition being proved by [ev_plus4] as a
function type, one interesting point becomes apparent: The second
argument's type, [even n], mentions the _value_ of the first
argument, [n].
While such _dependent types_ are not found in conventional
programming languages, they can be useful in programming too, as
the recent flurry of activity in the functional programming
community demonstrates. *)
(** Notice that both implication ([->]) and quantification ([forall])
correspond to functions on evidence. In fact, they are really the
same thing: [->] is just a shorthand for a degenerate use of
[forall] where there is no dependency, i.e., no need to give a
name to the type on the left-hand side of the arrow:
forall (x:nat), nat
= forall (_:nat), nat
= nat -> nat
*)
(** For example, consider this proposition: *)
Definition ev_plus2 : Prop :=
forall n, forall (E : even n), even (n + 2).
(** A proof term inhabiting this proposition would be a function
with two arguments: a number [n] and some evidence [E] that [n] is
even. But the name [E] for this evidence is not used in the rest
of the statement of [ev_plus2], so it's a bit silly to bother
making up a name for it. We could write it like this instead,
using the dummy identifier [_] in place of a real name: *)
Definition ev_plus2' : Prop :=
forall n, forall (_ : even n), even (n + 2).
(** Or, equivalently, we can write it in more familiar notation: *)
Definition ev_plus2'' : Prop :=
forall n, even n -> even (n + 2).
(** In general, "[P -> Q]" is just syntactic sugar for
"[forall (_:P), Q]". *)
(* ################################################################# *)
(** * Programming with Tactics *)
(** If we can build proofs by giving explicit terms rather than
executing tactic scripts, you may be wondering whether we can
build _programs_ using _tactics_ rather than explicit terms.
Naturally, the answer is yes! *)
Definition add1 : nat -> nat.
intro n.
Show Proof.
apply S.
Show Proof.
apply n. Defined.
Print add1.
(* ==>
add1 = fun n : nat => S n
: nat -> nat
*)
Compute add1 2.
(* ==> 3 : nat *)
(** Notice that we terminate the [Definition] with a [.] rather than
with [:=] followed by a term. This tells Coq to enter _proof
scripting mode_ to build an object of type [nat -> nat]. Also, we
terminate the proof with [Defined] rather than [Qed]; this makes
the definition _transparent_ so that it can be used in computation
like a normally-defined function. ([Qed]-defined objects are
opaque during computation.)
This feature is mainly useful for writing functions with dependent
types, which we won't explore much further in this book. But it
does illustrate the uniformity and orthogonality of the basic
ideas in Coq. *)
(* ################################################################# *)
(** * Logical Connectives as Inductive Types *)
(** Inductive definitions are powerful enough to express most of the
connectives we have seen so far. Indeed, only universal
quantification (with implication as a special case) is built into
Coq; all the others are defined inductively. We'll see these
definitions in this section. *)
Module Props.
(* ================================================================= *)
(** ** Conjunction *)
(** To prove that [P /\ Q] holds, we must present evidence for both
[P] and [Q]. Thus, it makes sense to define a proof object for [P
/\ Q] as consisting of a pair of two proofs: one for [P] and
another one for [Q]. This leads to the following definition. *)
Module And.
Inductive and (P Q : Prop) : Prop :=
| conj : P -> Q -> and P Q.
End And.
(** Notice the similarity with the definition of the [prod] type,
given in chapter [Poly]; the only difference is that [prod] takes
[Type] arguments, whereas [and] takes [Prop] arguments. *)
Print prod.
(* ===>
Inductive prod (X Y : Type) : Type :=
| pair : X -> Y -> X * Y. *)
(** This similarity should clarify why [destruct] and [intros]
patterns can be used on a conjunctive hypothesis. Case analysis
allows us to consider all possible ways in which [P /\ Q] was
proved -- here just one (the [conj] constructor).
Similarly, the [split] tactic actually works for any inductively
defined proposition with exactly one constructor. In particular,
it works for [and]: *)
Lemma and_comm : forall P Q : Prop, P /\ Q <-> Q /\ P.
Proof.
intros P Q. split.
- intros [HP HQ]. split.
+ apply HQ.
+ apply HP.
- intros [HQ HP]. split.
+ apply HP.
+ apply HQ.
Qed.
(** This shows why the inductive definition of [and] can be
manipulated by tactics as we've been doing. We can also use it to
build proofs directly, using pattern-matching. For instance: *)
Definition and_comm'_aux P Q (H : P /\ Q) : Q /\ P :=
match H with
| conj HP HQ => conj HQ HP
end.
Definition and_comm' P Q : P /\ Q <-> Q /\ P :=
conj (and_comm'_aux P Q) (and_comm'_aux Q P).
(** **** Exercise: 2 stars, standard, optional (conj_fact)
Construct a proof object demonstrating the following proposition. *)
Definition conj_fact : forall P Q R, P /\ Q -> Q /\ R -> P /\ R
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
(** [] *)
(* ================================================================= *)
(** ** Disjunction *)
(** The inductive definition of disjunction uses two constructors, one
for each side of the disjunct: *)
Module Or.
Inductive or (P Q : Prop) : Prop :=
| or_introl : P -> or P Q
| or_intror : Q -> or P Q.
End Or.
(** This declaration explains the behavior of the [destruct] tactic on
a disjunctive hypothesis, since the generated subgoals match the
shape of the [or_introl] and [or_intror] constructors.
Once again, we can also directly write proof objects for theorems
involving [or], without resorting to tactics. *)
(** **** Exercise: 2 stars, standard, optional (or_commut'')
Try to write down an explicit proof object for [or_commut] (without
using [Print] to peek at the ones we already defined!). *)
Definition or_comm : forall P Q, P \/ Q -> Q \/ P
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
(** [] *)
(* ================================================================= *)
(** ** Existential Quantification *)
(** To give evidence for an existential quantifier, we package a
witness [x] together with a proof that [x] satisfies the property
[P]: *)
Module Ex.
Inductive ex {A : Type} (P : A -> Prop) : Prop :=
| ex_intro : forall x : A, P x -> ex P.
End Ex.
(** This may benefit from a little unpacking. The core definition is
for a type former [ex] that can be used to build propositions of
the form [ex P], where [P] itself is a _function_ from witness
values in the type [A] to propositions. The [ex_intro]
constructor then offers a way of constructing evidence for [ex P],
given a witness [x] and a proof of [P x]. *)
(** The more familiar form [exists x, P x] desugars to an expression
involving [ex]: *)
Check ex (fun n => even n).
(* ===> exists n : nat, even n
: Prop *)
(** Here's how to define an explicit proof object involving [ex]: *)
Definition some_nat_is_even : exists n, even n :=
ex_intro even 4 (ev_SS 2 (ev_SS 0 ev_0)).
(** **** Exercise: 2 stars, standard, optional (ex_ev_Sn)
Complete the definition of the following proof object: *)
Definition ex_ev_Sn : ex (fun n => even (S n))
(* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted.
(** [] *)
(* ================================================================= *)
(** ** [True] and [False] *)
(** The inductive definition of the [True] proposition is simple: *)
Inductive True : Prop :=
| I : True.
(** It has one constructor (so every proof of [True] is the same, so
being given a proof of [True] is not informative.) *)
(** [False] is equally simple -- indeed, so simple it may look
syntactically wrong at first glance! *)
Inductive False : Prop := .
(** That is, [False] is an inductive type with _no_ constructors --
i.e., no way to build evidence for it. *)
End Props.
(* ################################################################# *)
(** * Equality *)
(** Even Coq's equality relation is not built in. It has the
following inductive definition. (Actually, the definition in the
standard library is a slight variant of this, which gives an
induction principle that is slightly easier to use.) *)
Module MyEquality.
Inductive eq {X:Type} : X -> X -> Prop :=
| eq_refl : forall x, eq x x.
Notation "x == y" := (eq x y)
(at level 70, no associativity)
: type_scope.
(** The way to think about this definition is that, given a set [X],
it defines a _family_ of propositions "[x] is equal to [y],"
indexed by pairs of values ([x] and [y]) from [X]. There is just
one way of constructing evidence for members of this family:
applying the constructor [eq_refl] to a type [X] and a single
value [x : X], which yields evidence that [x] is equal to [x].
Other types of the form [eq x y] where [x] and [y] are not the
same are thus uninhabited. *)
(** We can use [eq_refl] to construct evidence that, for example, [2 =
2]. Can we also use it to construct evidence that [1 + 1 = 2]?
Yes, we can. Indeed, it is the very same piece of evidence!
The reason is that Coq treats as "the same" any two terms that are
_convertible_ according to a simple set of computation rules.
These rules, which are similar to those used by [Compute], include
evaluation of function application, inlining of definitions, and
simplification of [match]es. *)
Lemma four: 2 + 2 == 1 + 3.
Proof.
apply eq_refl.
Qed.
(** The [reflexivity] tactic that we have used to prove equalities up
to now is essentially just shorthand for [apply eq_refl].
In tactic-based proofs of equality, the conversion rules are
normally hidden in uses of [simpl] (either explicit or implicit in
other tactics such as [reflexivity]).
But you can see them directly at work in the following explicit
proof objects: *)
Definition four' : 2 + 2 == 1 + 3 :=
eq_refl 4.
Definition singleton : forall (X:Type) (x:X), []++[x] == x::[] :=
fun (X:Type) (x:X) => eq_refl [x].
(** **** Exercise: 2 stars, standard (equality__leibniz_equality)
The inductive definition of equality implies _Leibniz equality_:
what we mean when we say "[x] and [y] are equal" is that every
property on [P] that is true of [x] is also true of [y]. *)
Lemma equality__leibniz_equality : forall (X : Type) (x y: X),
x == y -> forall P:X->Prop, P x -> P y.
Proof.
(* FILL IN HERE *) Admitted.
(** [] *)
(** **** Exercise: 5 stars, standard, optional (leibniz_equality__equality)
Show that, in fact, the inductive definition of equality is
_equivalent_ to Leibniz equality: *)
Lemma leibniz_equality__equality : forall (X : Type) (x y: X),
(forall P:X->Prop, P x -> P y) -> x == y.
Proof.
(* FILL IN HERE *) Admitted.
(** [] *)
End MyEquality.
(* ================================================================= *)
(** ** Inversion, Again *)
(** We've seen [inversion] used with both equality hypotheses and
hypotheses about inductively defined propositions. Now that we've
seen that these are actually the same thing, we're in a position
to take a closer look at how [inversion] behaves.
In general, the [inversion] tactic...
- takes a hypothesis [H] whose type [P] is inductively defined,
and
- for each constructor [C] in [P]'s definition,
- generates a new subgoal in which we assume [H] was
built with [C],
- adds the arguments (premises) of [C] to the context of
the subgoal as extra hypotheses,
- matches the conclusion (result type) of [C] against the
current goal and calculates a set of equalities that must
hold in order for [C] to be applicable,
- adds these equalities to the context (and, for convenience,
rewrites them in the goal), and
- if the equalities are not satisfiable (e.g., they involve
things like [S n = O]), immediately solves the subgoal. *)
(** _Example_: If we invert a hypothesis built with [or], there are
two constructors, so two subgoals get generated. The
conclusion (result type) of the constructor ([P \/ Q]) doesn't
place any restrictions on the form of [P] or [Q], so we don't get
any extra equalities in the context of the subgoal. *)
(** _Example_: If we invert a hypothesis built with [and], there is
only one constructor, so only one subgoal gets generated. Again,
the conclusion (result type) of the constructor ([P /\ Q]) doesn't
place any restrictions on the form of [P] or [Q], so we don't get
any extra equalities in the context of the subgoal. The
constructor does have two arguments, though, and these can be seen
in the context in the subgoal. *)
(** _Example_: If we invert a hypothesis built with [eq], there is
again only one constructor, so only one subgoal gets generated.
Now, though, the form of the [eq_refl] constructor does give us
some extra information: it tells us that the two arguments to [eq]
must be the same! The [inversion] tactic adds this fact to the
context. *)
(* Fri 30 Aug 2019 02:44:46 PM CEST *)